This second column taken from my new book Composites for Construction — Structural Design with FRP Materials (published by John Wiley & Sons Inc., New York, N.Y.) focuses on the design of concrete members that have FRP main tension reinforcing bars and are subjected to transverse shear forces (Chapter 6) and FRP reinforcement detail design (Chapter 7).
The flexural concrete members that fall into the scope of this column are slabs and beams. The design procedures presented here follow those of the American Concrete Institute (ACI) 440.1R06, which is compatible with ACI 31805 and follows the Load and Resistance Factor Design (LFRD) basis for strength with a resistance factor of ϕ = 0.75, the same factor that is used for steelreinforced concrete as per ACI 31805.
In a reinforced concrete section that develops a critical diagonal shear crack — one that initiates from a flexural crack at the bottom of the beam and propagates toward the top — the shear resistance comes from several sources: 1) the shear strength of the top portion of the beam, 2) frictional resistance between the two sides of the crack, known as aggregate interlock, 3) the vertical component of shear force carried in the main tensile reinforcement, or dowel action, which tends to prevent vertical crack growth, 4) the vertical force component provided by any additional reinforcing bars along the length of the beam, or shear reinforcement, and 5) any additional thrust provided by the compression arch, known as arching action, which develops in the beam roughly parallel to the shear cracks. Unfortunately, no analytical methods exist to quantitatively determine these factors — current practice is to lump everything, except for the shear reinforcement contribution, in a general category of shear capacity, or V_{c}. Typically, the value of V_{c }has been obtained empirically by testing beams that have steel main reinforcement but do not have shear reinforcement.
When an FRPreinforced section and a steelreinforced section are designed for the same momentcarrying capacity, the shear capacity of the FRPreinforced section is much lower than the latter for a variety of reasons, but research and testing have confirmed that the main reason is the lower longitudinal modulus of the glass FRP bars.
The nominal shear capacity, V_{n}, of an FRPreinforced beam, according to ACI 440.1R06, is given as
V_{n} = V_{c} + V_{f}
where Vc is the concrete’s contribution to shear resistance and Vf is the contribution from FRP shear reinforcement, typically in the form of stirrups (the “f” subscript denotes the use of FRP rather than steel). The stirrups are typically bent into a “U” or rectangular shape and installed perpendicular to the longitudinal reinforcing bars.
The method for calculating V_{c }has evolved over time; the current equation in ACI 440.1R06 (equation 91) is reproduced in Fig. 1, where b_{w }_{ }is the width of the beam web and c is the depth of the neutral axis in the cracked elastic section as defined for the serviceability limit state flexural behavior; serviceability limit state flexural behavior is defined in Chapter 5 of my book. Note that the equation above is the traditional equation for the concrete shear contribution, V_{c}, multiplied by 2.5k (k being the ratio of the depth of the neutral axis to the effective depth of the section under service loads). Because FRP bars have less axial stiffness than steel, both the value of k and the contribution to the shear capacity will be less than in the case of steel.
The shear capacity of FRP stirrups, V_{f}, is calculated using equations similar to those given for steel stirrups. Note that the design strength of an FRP stirrup can’t be used in place of the yield stress of a steel stirrup, because FRP doesn’t yield like steel. The stress in an FRP stirrup is limited by its tensile strain or by its strength at its bent portion — for best performance, a minimum inside radiustodiameter ratio of 3 is required for bent FRP stirrups, as per ACI 440.1R06. This is because of stresses induced in the FRP bars when they’re bent, which can lead to premature linearelastic failures.
As noted in my previous column (CT February 2007, p. 11), FRP bars can’t be bent in the field, unlike steel, and have to be produced with a bend by the manufacturer — typically only 90° bends are available. This requires close coordination with the manufacturer during the design phase to preorder stirrups to specific dimensions.
The design process for FRP shear reinforcement involves determining the shear demand, V_{u}, which is calculated in the same way as in ACI 31805, using the same loading as that used for the flexural design. The concrete's shear capacity, V_{c}, is calculated using the ACI 440.1R06 equation 91, shown above. If V_{u} ≥ 0.5ϕV_{c }, minimum FRP shear reinforcement must be provided, and if V_{u} ≥ ϕV_{c} additional FRP shear reinforcement, A_{fv}, must be provided. Use a resistance factor of ϕ = 0.75 to determine the factored shear strength of the member; if the shear demand is not met, revisit the overall beam design — greater beam thickness and/or more flexural reinforcement may be needed. Again, this is significantly different from a steelreinforced design, where shear usually does not control member thickness.
The devil is in the details
The strength and serviceability calculations described above and in my previous article are used to determine the crosssectional areas and bar sizes of the tension (main) and shearreinforcing bars in a beam or slab. These calculations do not, however, give the designer the length, spacing or location of the bars within the section, nor do they determine whether or not the bars are sufficiently anchored and embedded in the concrete throughout to ensure that calculated strengths will be obtained. This falls to "detailing," which is very important to the overall design and not a trivial constructionrelated item, as the term might imply.
To obtain bar spacing, the side distance for an FRP corner bar is calculated the same way as for steel. However, that minimum inside radiustodiameter ratio of 3 or more, mentioned above, must be enforced. Figure 1shows the geometry of the corner bar and the parameters, A, B and C (clear cover, stirrup diameter and inside stirrup radius), which are used to calculate this distance. For example, assuming a beam with a No. 3 stirrup with an inside bend radius of 2.125 inches/60 mm and a side clear cover of 1.5 inches/38.1 mm gives a distance to the center of the corner bar of
A + B + C = 1.5 + 0.375 + 2.125 = 4.0 inches
A fundamental assumption of concrete design is that a “perfect” bond exists between rebar and concrete and that all tensile forces are transferred. ACI 440.1R06 (equation 113) recommends that the maximum (effective) stress achievable in an FRP bar, which is controlled by bond failure, be taken as shown in Fig. 2, where C is the lesser of 1) the distance from the center of the bar to the nearest outer beam surface in the tension zone, or 2) half of the oncenter spacing of the bars (side by side) and α is the bar location factor. C is 1.0 for bars that are in the bottom 12 inches/305 mm of the formwork when the concrete is cast, and is 1.5 when the bars are more than 12 inches above the bottom of the formwork (top bars). ACI 440.1R06 further states that the term C/d_{b} (d_{b} being the bar diameter) not be taken larger than 3.5 and the minimum embedment length l_{e} be at least 20 bar diameters, or 20d_{b}.
The above equation indicates that the effective design strength of FRP rebar can be less than the maximum bar design strength based on tensile failure, primarily because FRP rebar has a very high strength relative to its modulus, compared to steel. This is unique to FRP bars and can complicate the design of flexural members because the details of placement are not precisely known at the time of initial design. To address this issue, sections that are bondcritical to the design of the beam and its capacity are obtained using the equations for an underreinforced beam, and a resistance factor of ϕ = 0.55 is recommended. Alternatively, the beam can be redesigned as an overreinforced beam using the lower bondcritical bar strength, and the resistance factor for an overreinforced beam can be used: 0.55 ≤ ϕ ≤ 0.65.
The required bar length is that needed to anchor the bar in the concrete firmly enough to develop the tensile stress necessary for internal moment equilibrium at any section. Because the FRP bar may not be stressed to its full longitudinal design strength, f_{fu}, at the maximum moment, the development length l_{d} is given in ACI 440.106 (equation 116) as shown in Fig. 3.
All other ACI 31805 provisions related to bars at inflection points and at bar cutoffs that are required for steel are also required for FRP. For simply supported beams, at least onethird of the main tension bars much extend over the support.
Excerpt published with permission. Copyright © 2007 John Wiley & Sons and Composites Technology. Composites for Construction — Structural Design with FRP Materials is available for $135 (USD) at www.wiley.com, or from www.bn.com, www.amazon.com or www.borders.com.
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